A chain of length l is lying in a smooth horizontal tube such that a fraction of its length h hangs freely and the end touches the ground. At a certain moment the other end of chain is set free. The speed of this end of chain when it slips out of the tube is
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
For hanging part,
mgh – T = mha …….. (i)
and for par in tube,
T = mxa ………….. (ii)
Adding the above equations, we get
mgh = m(h + x)a
or a = 
or 
or vdv =
dx
∴ ∴ 
i.e., v = 
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